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When David was done playing basketball outside, he left the ballinside during 291 K when the ball had 29 atm of pressure. However,someone increased the thermostat to 299 K. What will happen to thebasketball's PRESSURE the next morning?

Respuesta :

Explanation:

We are given: Initial temperature = 291 K

: Initial pressure = 29 atm

: Final temperature = 299 K

We use Guy-Lussac's law to find the final pressure:

[tex]\begin{gathered} \frac{P_1}{T_1}\text{ = }\frac{P_2}{T_2} \\ \therefore P_2\text{ = }\frac{P_1T_2}{T_1}\text{ = }\frac{29\text{ }\times\text{ 299}}{291}\text{ = 29.80 atm} \end{gathered}[/tex]

Answer:

The basketball's pressure will increase.