I need help with the last one.True vale of density = 0.9973g/cm3 at 24°C

Percent error is used to calculate the difference between the true value versus the value found experimentally. It is calculated with the following equation:
[tex]\text{Percent error =}\frac{\text{ True value-Experimental value}}{\text{True value}}\times100[/tex]Experimental value =0.994g/cm3
True value = 0.9973 g/cm3
Now, we will replace the known values in the equation:
[tex]\begin{gathered} \text{Percent error =}\frac{\text{ 0.9973g/cm}^3\text{-0}.994\text{g/cm}^3}{\text{0.9973g/cm}^3}\times100 \\ \text{Percent error =}0.33 \end{gathered}[/tex]So, the percent error will be 0.33%