Respuesta :
We are asked to determine the escape velocity of a planet of radius 6x10^7 m.
to do that we will use the fact that the escape velocity of a planet is given by the following formula:
[tex]v_e=\sqrt[]{2gR}[/tex]Where:
[tex]\begin{gathered} v_e=\text{ escape velocity, }\lbrack\frac{m}{s}\rbrack \\ g=\text{ magnitude of gravitational field,}\lbrack\frac{m}{s^2}\rbrack \\ R=\text{ radius of the planet, }\lbrack m\rbrack \end{gathered}[/tex]Now, we substitute the values:
[tex]v_e=\sqrt[]{2(42.9\frac{m}{s^2})(6\times10^7m)}[/tex]Solving the operations:
[tex]v_e=71749.6\frac{m}{s}[/tex]Therefore, the escape velocity is 71749.6 m/s.
