Let the missing divisor be x, thus we have:
[tex]\frac{1.8}{x}=60[/tex]Cross-multiply, we have:
[tex]60x=1.8[/tex]Divide both sides by the the co-efficient of x, which is 60, we have:
[tex]\begin{gathered} \frac{60x}{60}=\frac{1.8}{60} \\ x=0.03 \end{gathered}[/tex]Hence, the missing divisor is 0.03, option B
