Consider the first equation,
[tex]x+y=4[/tex]
We need at least two feasible points to draw the graph of the straight line.
So for the first equation (0,4) and (4,0) two of the many feasible points.
Similarly, consider the second equation,
[tex]2x-y=5[/tex]
This equation has the feasible points (3,1) and (4,3).
Now, plot these points and join them to get the corresponding lines on the graph.
