We simply multiply the two terms and remember the multiplication rule of exponents where we add the exponents when multiplying same base. Shown below:
[tex]a^x\times a^y=a^{x+y}[/tex]So, we multiply:
[tex]\mleft(\frac{7}{6}a^7b^2\mright)\mleft(5a^4b^6\mright)[/tex]Using the rule and multiplication, we have:
[tex]\begin{gathered} (\frac{7}{6}a^7b^2)(5a^4b^6) \\ =(\frac{7}{6})(5)a^7a^4b^2b^6 \\ =\frac{35}{6^{}}a^{11}b^8 \end{gathered}[/tex]This is the final answer.
