The radius of the circle is = 13
This is because, the line from the center of the circle bisects the chord AB, as shown below:
Now consider any of the two right triangles obtained, and apply the pythagorean theorem:
Applying the pythagorean theorem to obtain r:
[tex]\begin{gathered} r^2=5^2+12^2 \\ r^2=25^{}+144 \\ r^2\text{ = 169} \\ r\text{ =}\sqrt[]{169} \\ r\text{ = 13} \end{gathered}[/tex]
Therefore, the radius of the circle is r = 13
