Given:
Beam drops at 4.00in
The distance between car and point is 22 ft
Find-:
The angle between beam and road is:
Sol:
Convert "inch" into ft.
[tex]1\text{ in=0.0833 ft}[/tex]
So the 4 in is.
[tex]\begin{gathered} 1\text{ in =0.0833 ft} \\ \\ 4\times1\text{ in=4}\times0.0833ft \\ \\ 4\text{ in=0.3332 ft} \end{gathered}[/tex]
Use the property of triangle is:
[tex]\tan\theta=\frac{\text{ Perpendicular}}{\text{ Base}}[/tex]
[tex]\begin{gathered} \tan\theta=\frac{0.3332}{22} \\ \\ \tan\theta=0.015145 \\ \\ \theta=\tan^{-1}(0.015145) \\ \\ \theta=0.868 \end{gathered}[/tex]
So the angle is 0.868
