Solution:
Given that;
Subtract 1010 from 1001 in binary
Converting from binary to base ten (decimal value)
[tex]\begin{gathered} 1^30^21^10^0=1\times2^3+0\times2^2+1\times2^1+0\times2^0=8+0+2+0=10 \\ 1^30^20^11^0=1\times2^3+0\times2^2+0\times2^1+1\times2^0=8+0+0+1=9 \end{gathered}[/tex]
Subtracting the numbers
[tex]=10-9=1[/tex]
In binary,
Hence, the answer is 1
