The equation is given
[tex]25x^2+81y^2=1[/tex]
To determine y-intercept substitute x=0
[tex]0+81y^2=1[/tex][tex]y^2=\frac{1}{81}[/tex][tex]y=\sqrt[]{\frac{1}{81}}=\pm\frac{1}{9}[/tex]
To determine the x-intercept , substitute y=0
[tex]25x^2+0=1[/tex][tex]x^{}=\sqrt[]{\frac{1}{25}}=\pm\frac{1}{5}[/tex]
Hence the x-intercepts are
[tex]\frac{1}{5},-\frac{1}{5}[/tex]
The y-intercepts are
[tex]\frac{1}{9},\frac{-1}{9}[/tex]
