Respuesta :

Here, the given equation is 3(x+1)=5+x.

Opening the brackets implies,

[tex]3x+3=5+x[/tex]

Move variable terms to LHS and constants to RHS gives,

[tex]\begin{gathered} 3x-x=5-3 \\ 2x=2 \\ x=1 \end{gathered}[/tex]

Therefore, the value of x is 1.