ok
To solve this problem, I'll use the Pythagorean theorem
[tex]\text{ c}^2=a^2+b^2[/tex]
c = 25
a = 12
b = x
[tex]\begin{gathered} \text{ b = }\sqrt[]{c^2-a^2} \\ \text{ b = }\sqrt[]{25^2-12^2} \\ \text{ b = }\sqrt[]{625\text{ - 144}} \\ \text{ b = }\sqrt[]{481} \end{gathered}[/tex]
Result
b = 21.93 rounding to the nearest foot
b = 22 ft this is the distance.
