Answer:
[tex]m\measuredangle5=90+3x[/tex]
Step-by-step explanation:
If it is given that it is an isosceles triangle, then its base angles are equal in measure, if the segments bisect the base angles we would have the following diagram;
Then, if we want to find an expression for angle 5. Remember that all intern angles of a triangle must add up to 180 degrees, hence the expression would be:
[tex]\begin{gathered} m\measuredangle5=180-\left(90-6x\right)-\left(3x\right) \\ m\measuredangle5=180-90+6x-3x \\ m\measuredangle5=90+3x \end{gathered}[/tex]
