Respuesta :

USING COSINE RULE

[tex]\begin{gathered} \text{COS A=}\frac{b^2+c^2-a^2}{2bc} \\ \\ \text{where a=10, b=7 and c=6} \\ \text{COS A=}\frac{7^2+6^2-10^2}{2\times7\times6} \\ \text{COSA =}\frac{49+36-100}{84} \\ \text{COS }A=\text{ -0.17857} \\ A=\cos ^{-1}-0.17857 \\ A=100.286\approx100.3^0 \end{gathered}[/tex]

STEP 2

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