Given that slope =0.06.
The triangle is a right-angled triangle with base x and height y.
Here r is the length of the deck of the bridge.
y=the exact rise of the bridge.
x= the run of the bridge,
[tex]\text{Slope =}\frac{y}{x}=0.06[/tex]
[tex]\text{Slope =}\frac{y}{x}=\frac{6}{100}=\frac{3}{50}[/tex]
By using the Pythagorean theorem, we get the length r as follows.
[tex]r=\sqrt[]{x^2+y^2}[/tex]
Substitute x=50 and y=3, we get
[tex]r=\sqrt[]{50^2+3^2}=\sqrt[]{2500+9}=\sqrt[]{2509}=50.089[/tex]
The length of the bridge is 50.09.
