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If n=12, ¯x (x-bar)=34, and s=19, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. < μ <

If n12 x xbar34 and s19 construct a confidence interval at a 90 confidence level Assume the data came from a normally distributed populationGive your answers to class=

Respuesta :

n=12

s=19

X=34

ConfLevel=90%

A confidence level of 90%

represent a Z statistical of 1.645

the Confidence interval is given by

[tex]X\pm Z*\frac{s}{\sqrt{n}}[/tex]

then

[tex]34\pm1.645*\frac{19}{\sqrt{12}}[/tex][tex]34\pm9.02254[/tex]

then the interval is

[tex]25.0\leq u\leq43.0[/tex]

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