SOLUTION
The given expression is:
[tex]\log_6\frac{4x}{3}[/tex]
This is simplified to give
[tex]\operatorname{\log}_6\frac{4x}{3}=\operatorname{\log}_64x-\operatorname{\log}_63[/tex]
This further gives
[tex]\operatorname{\log}_64x-\operatorname{\log}_63=\operatorname{\log}_64+\operatorname{\log}_6x-\operatorname{\log}_63[/tex]
Therefore the required answer is:
[tex]\begin{equation*} \operatorname{\log}_64+\operatorname{\log}_6x-\operatorname{\log}_63 \end{equation*}[/tex]
