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For an object whose velocity in ft/sec is given by v(t) = -t^2 + 2, what is its displacement, in feet, on the interval t = 0 to t = 2 secs?

For an object whose velocity in ftsec is given by vt t2 2 what is its displacement in feet on the interval t 0 to t 2 secs class=

Respuesta :

Given:

[tex]v(t)=-t^2+2[/tex]

Required:

To calculate its displacement

Explanation:

Velocity is the derivative of displacement with respect to time.

v=dx/dt

In this case , we have the velocity but need to know the displacement

We integrate the velocity function with the bounds of t=0 to t=2s

[tex]\int_0^2t^2+2[/tex]

after calculating we get 1.333

Required answer:

Option A

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