Given:
The slope (m) of the line given is,
[tex]m=\frac{1}{8}[/tex]
The point given is,
[tex](-3,0)[/tex]
Required:
To draw the graph of the line that contains the given point and has the slope.
Explanation:
We have the given point,
[tex](x_1,y_1)=(-3,0)[/tex]
The slope of the line is,
[tex]m=\frac{1}{8}[/tex]
We know the slope-point form of the line given by,
[tex](y-y_1)=m(x-x_1)[/tex]
Therefore, using the given point and the slope in the above form, we get the equation of line as:
[tex]\begin{gathered} (y-0)=\frac{1}{8}(x-(-3)) \\ \Rightarrow y=\frac{1}{8}(x+3) \\ \Rightarrow y=\frac{x}{8}+\frac{3}{8} \end{gathered}[/tex]
The graph of the line containing the given point and the slope is shown below:
Final Answer:
The equation of the line is,
[tex]y=\frac{x}{8}+\frac{3}{8}[/tex]
The graph of the line is shown in the attachment.
