first we try to solve y using ln on both sides
[tex]\ln (10^y)=\ln (3)[/tex]using laws of logarithms we can put y multipliying
[tex]y\ln (10)=\ln (3)[/tex]and solve for y
[tex]\begin{gathered} y=\frac{\ln (3)}{\ln (10)} \\ \\ y\approx0.477 \end{gathered}[/tex]then right option is third, 0.48
