Respuesta :

[tex]\begin{gathered} sin^\theta=\text{ }\frac{opposite\text{ side}}{hypotenuse} \\ sin(20º)=\frac{19}{x} \\ x\text{ = }\frac{19}{sin20} \\ \\ x=\text{ }\frac{19}{0.34} \\ \\ x\approx\text{ 55.8} \end{gathered}[/tex]

x=55.8

For right angles you always have to remember this:

[tex]\begin{gathered} sin\theta=\text{ }\frac{opposite\text{ side}}{hypotenuse} \\ cos\theta=\text{ }\frac{adjacent\text{ side}}{hypotenuse} \\ tan\theta=\frac{adjacent\text{ side}}{opposite\text{ side}} \end{gathered}[/tex]

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