We are given two monomials
[tex]16jk^8m^5[/tex]
and
[tex]20j^9k^4m^6[/tex]
To find the lowest common multiple
we can express each of the monomials as follow
[tex]16jk^8m^5=16\times j\times k^8\times m^5[/tex]
[tex]20\times j^9\times k^4\times m^5[/tex]
For the number part of the monomials,
The multiples of 16 are: 16, 32, 48, 64, 80, 96,-----
The multiples of 20 are : 20, 40, 60, 80, 100,-----
The lowest common multiple of 16 and 20 is 80
For the alphabet parts, the alphabet with the highest power
[tex]\begin{gathered} \text{lowest common multiple of} \\ j\text{ and j}^9\text{ is j}^9 \\ k^4\text{ and }k^8\text{ is k}^8 \\ m^5\text{ and }m^6\text{ is m}^6 \end{gathered}[/tex]
If we combine the terms to give the lowest common multiple, we will obtain
[tex]80j^9k^8m^6[/tex]
Thus, Option C is correct
