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Line 1 passes through (-9,-4) and (-4,3). Line 2 passes through (7,-8) and (10,7). Why are the lines perpendicular? *1 pointSlope of line 1 is -1/5Slope of line 1 is -5Slope of line 1 is 5Slope of line 2 is -1/5Slope of line 2 is -5Slope of Line 2 is 5The slope of both lines are the same so they are perpindicularThe product of both slopes are -1 so they are perpendicular

Respuesta :

[tex]\text{Slope = }\frac{\text{ change in y}}{change\text{ in x}}[/tex]

For line 1

[tex]\begin{gathered} \text{Slope}=\text{ }\frac{3-(-4)}{-4-(-9)} \\ \\ =\frac{3+4}{-4+9} \\ =\frac{7}{5} \end{gathered}[/tex]

For line 2

[tex]\begin{gathered} \text{slope = }\frac{7-(-8)}{10-7} \\ =\frac{7+8}{3} \\ =\frac{15}{3} \\ =5 \end{gathered}[/tex]

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