Simplify the expression.
[tex]\begin{gathered} -\frac{2}{3}p+\frac{1}{5}-1+\frac{5}{6}p=-\frac{2}{3}p+\frac{5}{6}p+\frac{1}{5}-1 \\ =\frac{-2\cdot2p+5p}{6}+\frac{1-1\cdot5}{5} \\ =\frac{-4p+5p}{6}+\frac{1-5}{5} \\ =\frac{1}{6}p-\frac{4}{5} \end{gathered}[/tex]
So equivalent expression is,
[tex]\frac{1}{6}p-\frac{4}{5}[/tex]
