Respuesta :

Using Pythagoras' theorem;

[tex]\begin{gathered} 8^2=x^2+y^2----(1) \\ y^2=z^2+6^2----(2) \\ x^2=z^2+2^2-----(3) \end{gathered}[/tex][tex]\begin{gathered} From\text{ \lparen1\rparen;} \\ y^2=8^2-x^2----(a) \\ Sunstituting\text{ \lparen a\rparen into \lparen2\rparen} \\ 8^2-x^2=z^2+6^2 \\ x^2=-z^2+28----(4) \end{gathered}[/tex][tex]undefined[/tex]

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