1. Graph Quadrilateral QUAD with the following coordinates. Q-8, 0, U0, 6, A8, 0, D(0, -15).QUAD is a __________ because it has exactly 2 pairs ofconsecutive _________ sides. Its diagonals are ___________.2. The perimeter of QUAD is __________________units.The area of QUAD is _______ units2.

1 Graph Quadrilateral QUAD with the following coordinates Q8 0 U0 6 A8 0 D0 15QUAD is a because it has exactly 2 pairs ofconsecutive sides Its diagonals are 2 T class=
1 Graph Quadrilateral QUAD with the following coordinates Q8 0 U0 6 A8 0 D0 15QUAD is a because it has exactly 2 pairs ofconsecutive sides Its diagonals are 2 T class=

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Explanation

Part 1.

We graph the quadrilateral QUAD. For this, we plot and join the given ordered pairs.

As we can see, the quadrilateral QUAD is a kite because it has exactly 2 pairs of consecutive congruent sides.

Part 2.

Finding the perimeter

The perimeter is the sum of the length of all the sides of a polygon. Then, to calculate the perimeter of the quadrilateral QUAD, we have to find the measure of the segments UA and AD. For this, we can use the distance formula between two points.

[tex]\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{ Where }(x_1,y_1)\text{ and }(x_2,y_2)\text{ are the coordinates of the points.} \end{gathered}[/tex]

Then, we have:

• Measure of segment UA

[tex]\begin{gathered} (x_1,y_1)=U(0,6) \\ (x_2,y_2)=A(8,0) \\ d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt{(8-0)^2+(0-6)^2} \\ d=\sqrt{8^2+(-6)^2} \\ d=\sqrt{64+36} \\ d=\sqrt{100} \\ d=10 \end{gathered}[/tex]

• Measure of segment AD

[tex]\begin{gathered} (x_1,y_1)=A(8,0) \\ (x_2,y_2)=D(0,-15) \\ d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt{(0-8)^2+(-15-0)^2} \\ d=\sqrt{(-8)^2+(-15)^2} \\ d=\sqrt{64+225} \\ d=\sqrt{289} \\ d=17 \end{gathered}[/tex]

Now, we calculate the perimeter of the quadrilateral.

[tex]\begin{gathered} \text{ Perimeter }=\bar{UA}+\bar{AD}+\bar{DQ}+\bar{QU} \\ \text{ Perimeter }=10+17+17+10 \\ \text{ Perimeter }=54 \end{gathered}[/tex]

Therefore, the perimeter of QUAD is 54 units.

Finding the area

The area of a kite is half the product of the lengths of its diagonals.

[tex]A=\frac{1}{2}d_1*d_2[/tex]

Then, we have to calculate the measure of segments UD and QA to find the area of the kite. For this, we can use the distance formula between two points.

• Measure of segment UD

[tex]\begin{gathered} (x_1,y_1)=U(0,6) \\ (x_2,y_2)=D(0,-15) \\ d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt{(0-0)^2+(-15-6)^2} \\ d=\sqrt{0^2+(-21)^2} \\ d=\sqrt{0+21} \\ d=\sqrt{21} \\ d=21 \end{gathered}[/tex]

Ver imagen MaddieQ480554
Ver imagen MaddieQ480554