Respuesta :

The quadratic function is already written in a recognizable way:

[tex]f(x)=x^2-6x+11[/tex]

Evaluate the function at some values to find points on the graph of f:

[tex]\begin{gathered} \\ f(-1)=(-1)^2-6(-1)+11=18 \\ f(0)=(0)^2-6(0)+11=11 \\ f(1)=(1)^2-6(1)+11=6 \\ f(2)=(2)^2-6(2)+11=3 \\ f(3)=(3)^2-6(3)+11=2 \\ f(4)=(4)^2-6(4)+11=3 \\ f(5)=(5)^2-6(5)+11=6 \\ f(6)=(6)^2-6(6)+11=11 \\ f(7)=(7)^2-6(7)+11=18 \end{gathered}[/tex]

Plot the points (x,f(x)) on a coordinate plane:

Draw a smooth line through those points:

Ver imagen NoahjamesQ780592
Ver imagen NoahjamesQ780592