Since we have logarithms in base 6 in both sides, we have
[tex]\log _6x=\log _64\cdot8[/tex]because, one property of the logarithm (product rule) is
[tex]\log _ba+\text{lob}_bc=\log _ba\cdot c[/tex]since 4*8=32, we obtain
[tex]\log _6x=\log _632[/tex]by applying the inverse function to logarithms in both sides (logarithms have the same basis), the answer is
[tex]x=32[/tex]