The magnitude of the force F experienced by a charge q that moves in a direction perpendicular to a magnetic field B with a speed v is given by:
[tex]F=qvB[/tex]Isolate B from the equation:
[tex]B=\frac{F}{qv}[/tex]Replace F=22.394N, q=0.049C and v=272.4m/s to find the strength of the magnetic field:
[tex]B=\frac{22.394N}{(0.049C)(272.4\frac{m}{s})}=1.6778...T\approx1.7T[/tex]Therefore, the magnetic field strength is approximately 1.7T.
