Respuesta :
Question:
Write each of the following equations in y = mx + b form
Solution:
1) Let the equation
[tex]2y=\text{ -1x-8}[/tex]Dividing both sides of the equation by two, we have that this is equivalent to:
[tex]y\text{ = }\frac{-1}{2}x-\frac{8}{2}[/tex]this is equivalent to:
[tex]y\text{ = }\frac{-1}{2}x-4[/tex]Then the above equation is in the form y = mx +b.
2) Consider the following equation:
[tex]y-4\text{ = -3(x-3)}[/tex]adding to both sides of the equation the number 4, we get:
[tex]y\text{ = -3(x-3) + 4}[/tex]now, using the distributive property, we get:
[tex]y\text{ = -3x+9 + 4}[/tex]this is equivalent to:
[tex]y\text{ = -3x +13}[/tex]Then the above equation is in the form y = mx +b.
3) Let the following equation:
[tex]0.2x\text{ + 0.3y = 0.5}[/tex]subtracting to both sides of the equation the term 0.2x , we get:
[tex]\text{ 0.3y = 0.5}-0.2x[/tex]this is equivalent to:
[tex]\text{ 0.3y = }-0.2x+0.5[/tex]now, dividing both sides of the equation by 0.3, we have that this is equivalent to:
[tex]\text{ y = }\frac{-0.2}{0.3}x+\frac{0.5}{0.3}[/tex]this is equivalent to:
[tex]\text{ y = }\frac{-2}{3}x+\frac{5}{3}[/tex]Then the above equation is in the form y = mx +b.
4) Consider the following equation:
[tex]\frac{1}{4}y+3\text{ = -5x}[/tex]subtracting to both sides of the equation the number 3 , we get:
[tex]\frac{1}{4}y\text{ = -5x}-3[/tex]now, multiplying both sides of the equation by 4, we get:
[tex]y\text{ = -20x-12}[/tex]Then the above equation is in the form y = mx +b.
