Answer: [tex]Pr(rolling\text{ a 2 and 1\rparen= }\frac{1}{36}[/tex]
Explanation:
Given:
A six-sided die rolled twice
To find:
the probability of rolling a two and then a 1
To determine the probability, we need to find the probability of rolling a 2 and the probability of rolling a 1
Pr(rolling 2) = number of times 2 occurs/total
in a six-sided die, total = 6; and 2 occur once
[tex]Pr(rolling\text{ a 2\rparen = }\frac{1}{6}[/tex]
Pr(rolling 1) = umber of times 1 occurs/total
1 occur once
[tex]Pr(rolling\text{ 1\rparen = }\frac{1}{6}[/tex]
Pr(rolling a 2 and then 1) = Pr(rolling 2) × Pr(rolling 1)
[tex]\begin{gathered} Pr(rolling\text{ a 2 and 1\rparen = }\frac{1}{6}\text{ }\times\text{ }\frac{1}{6} \\ \\ Pr(rolling\text{ a 2 and 1\rparen = 1/36} \end{gathered}[/tex]
