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A warehouse has 12 and nine-tenths meters of tape in one area of the building, and eight and three-fifths meters of tape in another part. How much tape does the warehouse have in all?

Respuesta :

To solve this problem, we will add two mixed numbers, with the fractional parts having unlike denominators.

[tex]12\frac{9}{10}+8\frac{3}{5}=12\frac{9}{10}+8\frac{6}{10}=20\frac{15}{10}=21\frac{5}{10}=21\frac{1}{2}[/tex]

Then the answer is the mixed number 21 1/2

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