Respuesta :

[tex]x^2+y^2=r^2[/tex]

The circle is not at the origin, the center is at (-9,0) and has a radius of 8, then...

[tex](x-(-9))^2+(y-0)^2\text{ =}8^2[/tex]

Simplification:

[tex]\begin{gathered} (x^{}+9)^2+y^2=8^2 \\ \\ \end{gathered}[/tex]

Ver imagen MassimoI29037