Answer:
No Solution
Explanation:
Given the system of linear equations:
[tex]\begin{gathered} 3x+2y=4\ldots(1) \\ y=-\frac{3}{2}x+6\ldots(2) \end{gathered}[/tex]If we make y the subject of the equation in Equation 1, we have:
[tex]\begin{gathered} 2y=-3x+4 \\ y=-\frac{3}{2}x+\frac{4}{2} \\ y=-\frac{3}{2}x+2 \end{gathered}[/tex]The two equations are in the slope-intercept form: y=mx+b
We see that the coefficient of x in both equations is -3/2.
Therefore, the slopes of both lines = -3/2
Since the slopes are the same, the two lines are parallel.
Therefore, the system of equations has No Solution.
