From the problem, we have :
[tex]v^{\frac{1}{2}}+1=0[/tex]Subtract 1 to both sides of the equation :
[tex]\begin{gathered} v^{\frac{1}{2}}+1-1=-1 \\ v^{\frac{1}{2}}=-1 \end{gathered}[/tex]Square both sides :
[tex](v^{\frac{1}{2}})^2=(-1)^2[/tex]Note that the imaginary number i = √-1
and i^2 = (√-1)^2 = -1
We can replace the right side of the equation as :
[tex]\begin{gathered} (v^{\frac{1}{2}})^2=(-1)^2 \\ v=i^2 \end{gathered}[/tex]The answer is i^2
