We have the equation:
[tex]2x^2-2x+3[/tex]
Where:
a = 2
b = -2
c = 3
Using the formula:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
This is:
[tex]x=\frac{-(-2)\pm\sqrt[]{(-2)^2-4(2)(3)}}{2(2)}[/tex][tex]\begin{gathered} x=\frac{2\pm\sqrt[]{4-24}}{4} \\ x=\frac{2\pm\sqrt[]{-20}}{4}\text{ } \end{gathered}[/tex]
Answer:
[tex]\begin{gathered} x1=\frac{2+\sqrt[]{-20}}{4} \\ \text{and} \\ x2=\frac{2-\sqrt[]{-20}}{4} \end{gathered}[/tex]
