Answer:
(1)
[tex]y=(\frac{2}{s})x+(\frac{2}{s})[/tex](2)
[tex]y=(2)x+(-\frac{1}{2})[/tex]Explanation:
We needed to first write the system of equations in standard form, Note! the standard form is:
[tex]y(x)=mx+b[/tex]this can be done as follows:
[tex]\begin{gathered} (1)\rightarrow sy=2x+2\rightarrow y(x)=\frac{2}{s}x+\frac{2}{s} \\ (2)\rightarrow4x-2y\rightarrow y(x)=2x-\frac{1}{2} \end{gathered}[/tex]Slope and y-intercepts are:
(1)
[tex]\begin{gathered} m=\frac{2}{s} \\ b=\frac{2}{s} \end{gathered}[/tex](2)
[tex]\begin{gathered} m=2 \\ b=-\frac{1}{2} \end{gathered}[/tex]Therefore, these are the slope and y-intercepts of the two equations that we need to write in the box
