An airplane flies east at a speed of 120 m/s.
The airplane has a mass of 3200 kg.
A. Momentum:
The momentum of the airplane is given by
[tex]p=m\cdot v[/tex]Where m is the mass of the plane and v is the velocity of the plane.
[tex]p=3200\cdot120=384,000\; [/tex]Therefore, the momentum of the plane is 384,000 kg.m/s
B. New Velocity:
There is an Impulse of 44,000 kg*m/s west (opposite to east, so take it negative)
[tex]\begin{gathered} v_2=\frac{p_1-p_2}{m} \\ v_2=\frac{384,000-44,000}{3200} \\ v_2=106.25\; \end{gathered}[/tex]Therefore, the new velocity of the plane is 106.25 m/s
