Instructions: Solve the following systems of equations algebraically. If there are no real solutions, type “none” in both blanks. If there is only one, type “none” in the other blank.

Instructions Solve the following systems of equations algebraically If there are no real solutions type none in both blanks If there is only one type none in th class=

Respuesta :

Okay, here we have this:

Considering the provided system of equations, we are going to find the requested solutions, so we obtain the following:

So since the two equations are equal to y, we will proceed to equal them, we have:

y=-x-10

y=x^2-5x-10

Then:

-x-10=x^2-5x-10

0=x^2-5x+x-10+10

0=x^2-4x

0=x(x-4)

x=0 or x-4=0

x=0 or x=4

We will evaluate to know the values of "y" that are solutions:

x=0:

y=-x-10

y=-0-10

y=-10

x=4:

y=-x-10

y=-4-10

y=-14

Finally we obtain that the solutions are: (0, -10) (4, -14).