Respuesta :
In the given question 14,
There are 4 squares and 4 right triangles in the diagram.
The area of right triangle is determined by,
[tex]A_1=\frac{1}{2}\times b\times h[/tex]Here , b is the base of the right triangle and h is the height of the triangle.
The area of sqaure is ,
[tex]A_2=(side)^2[/tex]From the diagram, the side of square is 1 inch and base and height is also inch.
Substitute the values in the formula of triangle ,
[tex]A_1=\frac{1}{2}\times1\times1[/tex][tex]A_1=0.5in^2[/tex]The area of 4 right triangles is ,
[tex]A^{\prime}=4\times0.5=2in^2_{}[/tex]Substitute the value in the formula of square,
[tex]A_2=(1)^2[/tex]The area of 4 square is,
[tex]A^{\doubleprime}=4\times1=4in^2[/tex]The area of the figure obtained is ,
The sum of area of 4 square and area of 4 triangle.
[tex]A=2+4=6in^2\text{.}[/tex]