I need help finding x and y of this square.

5x-1 = 4 (diagonals of square bisects each other)
5x = 4+1
5x = 5
x = 5/5
x= 1
[tex]\begin{gathered} 2y=45^0\text{ (diagonals of square bisect angles corner angles into 45 degr}es\text{)} \\ y=\frac{45}{2} \\ y=22.5^0 \end{gathered}[/tex]