Given data
*The given time is t = 1 min
*Person walks the distance towards north is 20.0 m
*Person walks the distance towards west is 8.0 m
*Person walks the distance towrds south is 20.0 m
The diagram is given below
As the person firstly walks 20.0 m north, and then 8.0 m west, and then travels 20.0 m south. Hence, the displacement traveled by the person is s = 8.0 m.
The formula for the magnitude of the velocity is given as
[tex]v=\frac{s}{t}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} v=\frac{8.0}{1} \\ =8.0\text{ m/min} \end{gathered}[/tex]Hence, the magnitude of the velocity of the person is v = 8.0 m/min
The total distance traveled by the person is calculated as
[tex]\begin{gathered} d=20.0+8.0+20.0 \\ =48.0\text{ m} \end{gathered}[/tex]Hence, the total distance traveled by the person is d = 48.0 m
The formula for the speed is given as
[tex]u=\frac{d}{t}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} u=\frac{48.0}{1} \\ =48.0\text{ m/min} \end{gathered}[/tex]Hence, the speed is u = 48.0 m/min
