Respuesta :

Solution

For this case we have the following polynomial:

[tex]f(x)=3x^3-10x^2+11x-4[/tex]

3 -10 11 -4

1 3 -7 4

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3 -7 4

1 3 -4

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3 -4 0

Therefore we have:

[tex](x-1)(x-1)(3x-4)=0[/tex]

then tje zeros are:

[tex]x=1,x=\frac{4}{3}[/tex]

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