Given:
Function is
[tex]f(x)=9x^2-8[/tex]On interval [1, b]
Required:
Find the average rate of change?
Explanation:
The average rate change of f(x) on the interval. [a, b] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]We have that a = 1, b = b,
[tex]f(x)=9x^2-8[/tex]Thus
[tex]\begin{gathered} \frac{f(b)-f(a)}{b-a}=\frac{-8+9b^2-(-8+91^2)}{b-(-1)} \\ =\frac{9b^2-9}{b-1} \\ =9b+9 \end{gathered}[/tex]Answer:
Hence, this is the answer.
