Given that the initial moment of inertia is
[tex]I_i[/tex]
The final moment of inertia is
[tex]I_f=0.75I_i[/tex]
Let the initial angular velocity be
[tex]\omega_i[/tex]
Let the final angular velocity be
[tex]\omega_f[/tex]
The ratio of final and initial kinetic energy is
[tex]\begin{gathered} \frac{K_f}{K_i}=\frac{\frac{1}{2}I_i(\omega_i)^2}{\frac{1}{2}I_f(\omega_f)^2} \\ =\frac{I_i(\omega_i)^2}{0.75I_i(\omega_f)^2} \\ =\frac{(\omega_i)^2_{}}{0.75(\omega_f)^2} \\ =1.3\frac{(\omega_i)^2}{(\omega_f)^2} \end{gathered}[/tex]
