We have the function:
[tex]h(x)=8^x[/tex]
We have to find how h(x) change over the interval from x = 8 to x = 9.
We can find this as:
[tex]\frac{h(9)-h(8)}{h(8)}=\frac{h(9)}{h(8)}-1=\frac{8^9}{8^8}-1=8^{9-1}-1=8-1=7[/tex]
The value of h(9) is 8 times the value of h(8), so this is an increase of 7 times the value of h(8). This can be expressed as "h(x) increases by 700%".
Answer: h(x) increasees by 700%.
