1) In this problem, to find which value makes this function undefined we need to focus on the denominator:
[tex]\frac{8n-5}{3n+1}[/tex]So focusing on the denominator let's equate that to zero, and solve it for n:
[tex]\begin{gathered} 3n+1=0 \\ 3n+1-1=0-1 \\ 3n=-1 \\ \frac{3n}{3}=-\frac{1}{3} \\ n=-\frac{1}{3} \end{gathered}[/tex]2) So, we can tell that the value that makes this rational expression is defined is
[tex]n=-\frac{1}{3}[/tex]Because if we plug that into the expression, we'll get 0 on the denominator. And divisions by 0 are undefined.
