The equation below describes a circle. What are the coordinates of the centerof the circle?(x-4)^2 + (y+12)^2 = 17²O A. (4,12)OB. (-4,-12)O C. (-4,12)OD. (4, -12)21

Solution:
The equation is given below as
[tex](x-4)^2+(y+12)^2=17^2[/tex]Concept:
The general equation of a circle is given below as
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ where, \\ (h,k)=center \end{gathered}[/tex]Hence,
By comparing coefficients, we will have the center of the circle be
[tex](h,k)\Rightarrow(4,-12)[/tex]Hence,
The final answer is
[tex]\Rightarrow(4,-12)[/tex]OPTION D is the right answer