Answer:
The carton holds 8.9 ounces of yoghurt
Explanation:
The upper diameter, D = 2 in
R = D/2
R = 2/2
The upper radius, R = 1 inch
[tex]\begin{gathered} \text{The lower diameter, d= 2}\frac{7}{16}\text{ in = }2.4375 \\ \text{The lower radius, r = }\frac{d}{2}=\text{ }\frac{2.4375}{2}in\text{ = }1.22\text{ in} \end{gathered}[/tex]
The height, h = 3 in
The volume of the cone frustrum is:
[tex]\begin{gathered} V=\frac{1}{3}\pi h(R^2+r^2+Rr) \\ V=\frac{1}{3}\times3.142\times3(1^2+1.22^2_{}+1.22(1)) \\ V=3.142(3.7084)) \\ V=11.65in^3 \end{gathered}[/tex]
1.805 in.³ = 1 ounce
11.65in.³ = 11.65/1.805 ounce
11.65in.³ = 6.5 ounces
The carton holds 6.5 ounces of yoghurt
