Respuesta :

Given:

The total number digits =8

The number of digits in the pin =4

The number of four-digit pin=

[tex]8C_4=\frac{8!}{4!(8-4)!}[/tex]

[tex]=\frac{8!}{4!\times4!}=\frac{8\times7\times6\times5\times4!}{4\times3\times2\times4!}=2\times7\times5=70[/tex]

There is 70 possible four-digit pin.